Thats why you need to know geometry
volume is area times height, so 85mm^2 x 4mm = 340mm^3 and maybe expect 270mm^3 output. I dont know the if the physical limits will alow that, or transfer pump pressure will be able to fill it fast enough, especially as RPMs increase and there is less and less time.
for a 14mm plunger which is 75% larger than a 0.31" plunger........pi x radius^2 = (14mm/2)^2 x pi = area of circular plunger = 154mm^2. If there are two of them, that is 308 square millimeters of area times 4mm height (which is the lift) equals 1232 cubuc millimeters, or expect almost 1000mm^3 output. That is 1000cc per 1000 strokes, or 1cc per stroke, which would take some serious transfer pressure to fill that volume in 1.5 milliseconds at 4000rpm. What engine uses an IP like that?